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Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 投票中
Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 投票中
國一下數學函數求解 (急)
Jun 1st 2013, 02:58

1.已知f(x)=-3,則f(-3)+f(3)=?
f(x)=-3 <---這是一個常數函數。不管你的x是多少,結果都是-3
f(-3)+f(3)= -3-3=- 6

2. 若f(3a+2)=5a-7,則f(-4)=?
f(-4) 則 3a+2=-4 ,a=-2
則f(-4)=5×(-2)-7=-17

3. 若閏年(一年有366天)中,x月份的天數以f)x)表示,則f(2)=?
f(2)代表閏年的2月份的天數,則f(2)=29

4. 若函數g(x)=3x+8,在x=a的函數值是14,在x=b的函數值是2,則a+b=?
g(a)=3a+8=14,a=2
g(b)=3b+8=2,b=-2
a+b=2-2=0

5. 若函數f(x)=7-1,則:(1)f(x)在x=7的函數值為何? (2)若f(x)在x=-2的函數值為何?
(題目有沒有打錯??)
若f(x)=7x-1
x=7==>f(7)=7×7-1=13
x=-2==>f(-2)=7×(-2)-1=-15

6. 已知兩函數f(x)=2x-3,g(x)=3x-2,在x=a時的函數值相同,則a=?
f(a)=2a-3,
g(a)=3a-2
f(a) = g(a),2a-3=3a-2
a=-1

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